Answer: 1) b. 20° 2) a. 4 3) a. 4 4) c. 34°Step-by-step explanation:1) Since TV bisects ∠STU, then ∠UTV = ∠STV and 2(∠UTV) = ∠STV∠UTV = ∠STV x + 2 = [tex]\dfrac{1}{4}x[/tex]+84x + 8 = x + 32 multiplied by 4 to clear the denominator3x + 8 = 32 subtracted x from both sides3x = 24 subtracted 8 from both sides x = 8 divided both sides by 32(∠UTV) = ∠STV2(x + 2) = ∠STV2(8 + 2) = ∠STV 2(10) = ∠STV 20 = ∠STV*******************************************************************************2) Since SR bisects ST, then 2(SR) = ST2(SR) = ST2(3x + 3) = 30 3x + 3 = 15 divided both sides by 2 3x = 12 subtracted 3 from both sides x = 4 divided both sides by 3*********************************************************************************3) Since K is the midpoint of JL, then 2(JK) = JL2(JK) = JL 2(7) = 4x - 2 14 = 4x - 2 multiplied 2 and 7 16 = 4x added 2 to both sides 4 = x divided 4 from both sides*********************************************************************************4) Since QS is the midpoint, then 2(∠PQS) = ∠PQR2(∠PQS) = ∠PQR2(5y - 1) = 8y + 12 10y - 2 = 8y + 12 2y - 2 = 12 subtracted 8y from both sides 2y = 14 added 2 to both sides y = 7 divided 2 from both sides∠PQS = 5y - 1 = 5(7) - 1 = 35 - 1 = 34