The perimeter of the triangle shown are equal. Find the side lengths of each triangle.
Accepted Solution
A:
Good morning βοΈ___________________Step-by-step explanation:Let p1 be the perimeter of triangle ABC p2 be the perimeter of triangle PQRp1=(2x+4)+(2x+3)+(2x) = 6x+7p2=(2x)+(2x)+(3x+1) = 7x+1p1=p2 β 6x+7=7x+1 β 7x-6x=7-1 βx=6Then :AC=2(6)=12AB=2(6)+4=16BC=2(6)+3=15PQ=12QR=12PR=3(6)+1=19._____:)